Now, once you understand all that, you can look up manifest files. If you say java -jar x\MathStuff.jar, then it has to be in x in test, and you can also say c:\x\MathStuff.jar so it won't matter what your current directory is. Note that, if you specify the jar file as a relative name, then your current directory will have to be in the right relative position if you are, again, in c:\test\, and you want to say "java -jar MathStuff.jar", then MathStuff.jar has to be in the current directory.
Java jar file path command linux full#
So if you create your jar to have relative paths so that Matrix is in com/iona/math within the jar file (and you have remembered to NOT store it with the full path in front of com), then the classpath can contain the jar file and your program will have access to Matrix.
Java jar file path command linux zip#
If you have a jar file, then realize that a jar file is a specific kind of zip file, and zip files store directory structures as well as file names. Often the 'current directory', a concept common to most environments, is on the classpath if your current directory is c:\test\, and com is in that directory, and "." (the symbol for the current directory) is in the class path, then you can run your program and it can import and use Matrix. The next question is, where does com need to go? So if you're running a class in a package named, and the class is named Matrix, then you can put Matrix.class into a directory named math in a directory named iona in a directory named com (on Windows, com\iona\math\Matrix.class). The directory path to a java class is determined by its package you can put class files on a disk in a directory structure and run them from there IF your JVM has the root directory of that structure on its classpath. I do not know if I will get back in a few hours to solve the specific problem or not, but I think this is more important. I am short of time this evening, so I am just going to get down a few principles that you should know and point you to some things you might be able to look up yourself. Too many examples, not enough explanation of principle. It is a place where the shell and the java environment have to cooperate a little, and the explanations I've seen for it are confusing. S/He's trying to run a java program, and one has to understand how the classes are found (and not found) to do that. Java -Xms512m -Xmx512m -jar RR_Jar\NOPARAM_PDF.jar "/FBC Reports/EOM Reports/Byo Corp/Byo Credit gr/Byo Credit gr.xdo" "Reports\EOM\Byo Corp\Byo Credit gr.pdf" So i want to know how the system is picking up D:\BIP>java and D:\BIP\Batches>java location when i run it from a different folder. Unable to access jarfile RR_Jar\NOPARAM_PDF.jar Now if i change the location of batch from D:\BIP\Batches\ to D:\BIP\Batches\EOD\ it fails saying the below.ĭ:\BIP\Batches>java -Xms512m -Xmx512m -jar RR_Jar\NOPARAM_PDF.jar "/FBC Reports/ĮOM Reports/Byo Corp/Byo Credit gr/Byo Credit gr.xdo" "Reports\EOM\Byo Corp\By Rts/Byo Corp/Byo Credit gr/Byo Credit gr.xdo" "Reports\EOM\Byo Corp\Byo Credit Below is the result.ĭ:\BIP>java -Xms512m -Xmx512m -jar RR_Jar\NOPARAM_PDF.jar "/FBC Reports/EOM Repo With this folder structure the batch is running successfully. jar in the location D:\BIP\RR_Jar\ and the batch file in the location D:\BIP\Batches\
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